Question

In figure $\angle ABC={75}^o,\angle EDC={75}^o$ state which two triangles are similar and by which test?

Answer 1

We have,

In triangle,

$\Delta ABC$ and $\Delta DEC$

So,

$\angle ACB=\angle DCE\left(Commonangle\right)$

$\angle CDE=\angle ABC\left(eachgiven{75}^o\right)$

Now,

Hence, by AA similarity .

The two triangles $\Delta ABC$ and $\Delta CDE$ are similar.

Hence, this is the answer.