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Question

In figure, ACD=120 and APB=100 ,
(i) find x and y.
(ii) If BAC=2.5y, find ABC.


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Solution

(i)x+100=180 [Linear pair of angles]

x=80

Now, we have,

x+y=120 [Sum of interior opposite angles is equal to the exterior angle]

80+y=120

y=40

So, x=80,y=40​.

(ii)BAC=2.5y,

BAC=2.5×40=100

BAC+ABC=120 [Sum of interior opposite angles is equal to the exterior angle]

ABC=120100

ABC=20


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