In figure, ∠RST=56∘, seg PT ⊥ ray ST, seg PR ⊥ ray SR and seg PR ≅ seg PT. Find the measure of ∠RSP. State thr reason for your answer.
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Solution
Given seg PT ⊥ ray ST
seg PR ⊥ ray SR
seg PR ≅ seg PT
Any point equidistant from sides of an angle is on the bisector of the angle.
P is a point on the bisector of TSR. ∠RST=56∘ [Given] ∠RSP=12∠RST [Bisector of an angle divides it into two equal angles] ∠RSP =12×56∘=28∘
Hence measure of ∠RSPis28∘.