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Question

In figure, AP =2 cm, BQ = 3 cm and RC =4 cm, then find the perimeter of ΔABC
1200682_276ece97aac0494c80c37a4368ae4171.png

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Solution

REF.Image.
As the know that two tangents drawn from an
external point to the circle are equal in length.
so,
AR=AP=2cm
BQ=BP=3cm
RC=QC=4cm

Perimeter =AB+AC+BC
=(AR+RC)+(CQ+BQ)+(AP+BP)
=(2+4)+(4+3)+(2+3)
=6+7+5
=18cm

1113747_1200682_ans_dc250cbec0104fd5a72cdf5e8be77294.png

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