Question

In Figure, $BA||ED$ and $BC||EF.$ Show that $\angle ABC=\angle DEF$

Answer 1

In the figure, produce $DE$ to meet $AB$ at $P$

Given, $AB||DE$

$⟹\angle ABC=\angle DPC$ ---(corresponding angles)----(1)

Similarly, $EF||BC$

$⟹\angle DPC=\angle DEF$ ---(corresponding angles)----(2)

$\therefore \angle ABC=\angle DEF$----From(1) and (2)