In figure, certain mass of gas traces three paths 1,2,3 from state P to state Q. If the work done by the gas along three paths are W1,W2,W3 respectively, then
A
W1<W2<W3
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B
W1=W2=W3
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C
W1>W2>W3
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D
Data insufficient
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Solution
The correct option is CW1>W2>W3 Area under P−V graph gives workdone. ∴ Work done in 1st process is greater than 2nd and 3rd process. It is clearly evident from given figure that area under 2nd process is greater than area under 3rd process. ∴ We can conclude that, W1>W2>W3