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Standard XII

Physics

Mixed Combination of Cells

In Figure cir...

Question

In Figure circuit section, AB absorbs energy at a rate of 50W when a current i = 1.0 A passes through it in the indicated direction. What is the potential difference between A and B?

10 V

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50 V

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20 V

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30 V

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Solution

The correct option is B $50 V$
As section AB consumes power $P = 50 W$ at current $I = 1 A$ .
So, $P = V I$
$50 = (V_{A} - V_{B}) \times 1 \Rightarrow V_{A} - V_{B} = 50 V$

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In Figure circuit section, AB absorbs energy at a rate of 50W when a current i = 1.0 A passes through it in the indicated direction. What is the potential difference between A and B?

The correct option is B 50VAs section AB consumes power P=50W at current I=1A.So, P=VI50=(VA−VB)×1⇒VA−VB=50V

The correct option is B $50 V$
As section AB consumes power $P = 50 W$ at current $I = 1 A$ .
So, $P = V I$
$50 = (V_{A} - V_{B}) \times 1 \Rightarrow V_{A} - V_{B} = 50 V$