Question

In figure, DE $\parallel BC$ in $\Delta ABC$ such that $BC=8cm,AB=6cm$ and $DA=1.5cm$ . Find $DE$

Answer 1

$AsSE||BC,hence\Delta ABCand\Delta ADEareSimilartriangles\therefore \left(\frac{DE}{CB}\right)=\left(\frac{AD}{AB}\right)or\left(\frac{DE}{8}\right)=\left(\frac{1.5}{6}\right)\therefore DE=(\frac{1.5}{6}\cdot 8)=2cm$