Question

In figure, DE∥BCDE∥BC

Answer 1

We have $DE||BC$

Therefore $\dfrac{AD}{DB}=\dfrac{AE}{EC}

$\Rightarrow \frac{1.5}{3}=\frac{1}{EC}$

$\Rightarrow EC=\frac{3}{1.5}$

$\Rightarrow EC=2cm$