Question

In figure, $\Delta$UVW is right angled triangle and $\angle$UVW $=$ 90${}^o$, UV $=$ 6cm, and UW $=$ 8 cm, $\sin$ W = $p:m$, then $p+m$ =

Answer 1

Given: $△UVW$, $\angle UVW={90}^{\circ }$, $UV=6$ cm, $UW=8$ cm
By Pythagoras theorem,
$U{V}^2+V{W}^2=U{W}^2$
$6^2+V{W}^2=8^2$
$V{W}^2=28$
$VW=2\sqrt{7}$ cm
Trigonometric ratio w.r.t $\angle W$
$SinW=\frac{P}{H}=\frac{UV}{UW}=\frac{6}{8}=\frac{3}{4}$