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Question

In figure, ABDEPQ and ABC=130o,CDE=110o. Find BCD.
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A
30o
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B
60o
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C
110o
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D
130o
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Solution

The correct option is A 60o
PQDE
CDE+DCQ=180o (co-interior angles are supplementary)
110o+DCQ=180o(CDE=110o)
DCQ=70o
Similarly, ABPQ
ABC+PCB=180o (co-interior angles are supplementary)
130o+PCB=180o(ABC=130o)
PCB=50o
PCB+BCD+DCQ=180o (Angle on same side of straight line)
50o+BCD+70p=180o
BCD=180o50o70o
=60o

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