Question

In figure, $\angle AOC+\angle BOD={110}^o$. Then find the value of $\angle COD$ is:

• A. ${110}^o$
• B. ${90}^o$
• C. ${80}^o$
• D. ${70}^o$

Answer 1

Answer: (D)

${70}^o$

As we know that,
$\angle AOC+\angle COD+\angle BOD={180}^o$ (Angle on the same side of straight line)
${110}^o+\angle COD={180}^o$
${110}^o+\angle COD={180}^o$
$\angle COD={180}^o-{110}^o$
$={70}^o$