Question

In figure, draw a tackle to lift the load by applying the force in the downward direction. If the load is raised by 1 m, through what distance will the effort move?

Answer 1

Given:
The block and tackle system consists of 5
pulleys, i.e. $n=5$.
Velocity ratio of block and tackle system of n
pulleys is
$V.R.=\frac{d_E}{d_L}=n$
$d_E=n{d}_L$
In a system of $n=5$ pulleys, if the load moves up through a distance d, each segment of string supporting the load gets loosened by a length $d$.

So, if $d_L=1m$ then distance moved by the effort end is $d_E=n{d}_L=5\left(1m\right)=5m$