In figure, express x in terms of a,b and c.
In △KPN and △KLM, we have ∠KNP=∠KML=46o [Given] ∠K=∠K [Common] ∴△KNP∼△KML [By AA-criterion of similarity] ⇒KNKM=NPML [∴ Corresponding sides of similar triangles are proportional] ⇒cb+c=xa⇒x=acb+c