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Question

In figure, if AB=AC and AP=AQ, then by which congruence criterion ΔPBCΔQCB?

85216_57077f0aac474168a5790232927a8e2a.png

A
SSS
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B
ASA
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C
SAS
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D
RHS
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Solution

The correct option is C SAS
In the given triangle:
AB=AC
B=C (As angles opposite to equal to opposite sides are equal.
AB=AC
AP+PB=AQ+QC
Now AP=AQ
PB=QC
Now in PBC and QCB
PB=QC (Proved above)
B=C (Proved above)
BC=CB (Common side)
PBCQCB by SAS criteria.



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