Given, AB ∥ CD, CD ∥ EF and y:z = 3:7.
Since, AB ∥ CD and CD ∥ EF then AB ∥ EF.
Hence x = z (Alternate exterior angles are equal).
And x + y = 180° (Sum of co-interior angles is 180°).
We can write, y + z = 180°
Let, y = 3a and z = 7a
(y :z = 3 :7, given).
So, y + z = 180°
3a + 7a = 180°
10a = 180°
a = 18.
Since x = z = 7a
Then x = 7×18 = 126°