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Question
In figure, if ∠D=∠C then it is true that ΔADE∼ΔACB,? Why?
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Solution
True
In ΔADE and ΔACB,
∠A=∠A [ common angle]
∠D=∠C [given]
ΔADE∼ΔACB [ by AAA similarity criterion ]
In ΔADE and ΔACB,
∠A=∠A [ common angle]
∠D=∠C [given]
ΔADE∼ΔACB [ by AAA similarity criterion ]
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