Question

In figure if $BA\parallel DF,AD\parallel FG,\angle BAC={65}^o$ and $\angle ACB={55}^o$, then find $\angle FGH$.

• A. $\angle FGH={125}^o$
• B. $\angle FGH={145}^o$
• C. $\angle FGH={65}^o$
• D. $\angle FGH={55}^o$

Answer 1

The correct option is A $\angle FGH={125}^o$

In $△ABC$,
$\angle ACB+\angle ACE={180}^{\circ }$ (Linear pair)
$55+\angle ACE={180}^{\circ }$
$\angle ACE={125}^{\circ }$
Now, given, $AD\parallel FG$,
$\angle ACE=\angle FGH={125}^{\circ }$ (Corresponding angles of parallel lines)