Question

In figure, if ray BA || ray DE,∠C=50° and ∠D=100°. Find the measure of ∠ABC.

Answer 1

$\angle ABC=130°$

Step-by-step explanation:

Let draw a line Parallel to $BA$ & $DE$ passing through $C$

Line is $PQ$ passing through $C$

$PQ||BA||DE$

$\angle DCP=\angle CDE$

$=>\angle DCP=100°$

$\angle DCP+\angle DCQ=180°$

$100°+\angle DCQ=180°$

$\angle DCQ=80°$

$\angle PCB=\angle DCQ+\angle DCB$

$=>\angle PCB=80°+50°$

$=>\angle PCB=130°$

$\angle ABC=\angle PCB$

$=>\angle ABC=130°$