Question

In figure, it is given that $AB=CD$ and $AD=BC$. Prove that $△ADC\cong △CBA$.

Answer 1

In $\Delta ADC$ and $\Delta CBA$

$AB=CD$ (Given)

$AD=BC$ (Given)

$CA=CA$ (common)

Hence $\Delta ADC\cong \Delta CBA$ by SSS congruence rule