It is given that ∠1:∠2=3:2. So, let
∠1=3x° and ∠2=2x°
But ∠1 and ∠2 from a linear pair.
∴∠1+∠2=180°
⇒3x°+2x°=180°⇒5x°=180°
⇒x=180°5=36°
∴∠1=3x°=(3×36)°=108°
and, ∠2=2x°=(2×36°)=72°
Now, ∠1=∠3 and ∠2=∠4 [Vertically opposite angles]
∴∠4=72° and ∠3=108°
Now, ∠6=∠2 and ∠3=∠7 [Corresponding angles]
⇒∠6=72° and ∠7=108°[∠2=72°]
[Vertically opposite angles]
Again, ∠5=∠7 and ∠8=∠6
∴∠5=108° and ∠8=72°
Hence, ∠1=108°,∠2=72°,∠3=108°,∠4=72°,∠5=108°,∠6=72°,∠7=108° and ∠8=72°