Question

In figure, $O$ is center of circle and $\angle PQR={115}^0,\angle POR$ will be

• A. ${130}^0$
• B. ${230}^0$
• C. ${270}^0$
• D. ${360}^0$

Answer 1

The correct option is A ${130}^0$

Major angle $\angle POR=2\angle PQR$
$x=2\times {115}^o$
$x={230}^0$
Sum of angles formed at center of circle is ${360}^0$
$\therefore \angle POR+x={360}^0$
$\angle POR+{230}^0={360}^0$
$\angle POR={360}^0–{230}^0$
$\angle POR={130}^0$
Thus, (A) is correct.