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Question

In figure, ¯¯¯¯¯¯¯ST and ¯¯¯¯¯¯¯¯¯QR are parallel, ¯¯¯¯¯¯¯¯RU and ¯¯¯¯¯¯¯¯QT are perpendicular, RQU=x+4, and mQTS=2x30. Calculate the measure of QRU.
493216_4c173a7251b04977a67505dc3b379b23.png

A
34
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B
38
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C
52
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D
68
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E
88
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Solution

The correct option is C 52
Given ST and QR are parallel, RU and QT are perpendicular.
RQU=x+4 and QST=2x30
Given ST and QR are parallel and line QT cut both lines.
Then QST=RQU
2x30=x+4
2xx=4+30
x=34
Then RQU=34+4=380
In ΔQUR
Then QRU+RQU+QUR=180
QRU=18038+90=520

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