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Standard XII

Physics

Introduction

In figure par...

Question

In figure particle is shown travelling counterclockwise in circle of radius 10 m. The acceleration vector is indicated at a specific time. The value of ‘v’ at this time is

10 m/s

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15 m/s

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20 m/s

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7 m/s

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Solution

The correct option is C 20 m/s
$50 c o s 37^{\circ} = \frac{v^{2}}{R} \Rightarrow 40 = \frac{v^{2}}{10}; v = 20 m / s$

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In figure particle is shown travelling counterclockwise in circle of radius 10 m. The acceleration vector is indicated at a specific time. The value of ‘v’ at this time is

The correct option is C 20 m/s50cos37∘=v2R⇒40=v210;v=20m/s

The correct option is C 20 m/s
$50 c o s 37^{\circ} = \frac{v^{2}}{R} \Rightarrow 40 = \frac{v^{2}}{10}; v = 20 m / s$