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Question

In Figure, PS = QR and SPQ=RQP.


Prove that PR = QS and QPR=PQS.

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Solution

In ΔSPQ and ΔRQP, we have
PS = QR [Given]
SPQ=RQP [Given]
PQ = PQ [Common]
Therefore, by SAS criterion of congruence, we have
ΔSPQΔRQP
SQ=RP and QPR=PQS (c.p.c.t.)

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