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Standard XII

Chemistry

Hess' Law

In figure sho...

Question

In figure shown, the spring constant is k. The mass of the upper block is m and that of the lower back is 3m. The upper block is depressed down from its equilibrium position by a distance δ and released at t = 0.

The value of $δ$ for which the minimum normal reaction on 3m from ground is less than mg is

3mg/2k

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5 mg/2k

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3mg/k

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mg/2k

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Solution

The correct option is C
3mg/k

$m g + k (δ - \frac{m g}{k}) = 3 m g$ or $δ = \frac{3 m g}{k}$

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The correct option is C 3mg/k mg+k(δ−mgk)=3mg or δ=3mgk

The correct option is C
3mg/k

$m g + k (δ - \frac{m g}{k}) = 3 m g$ or $δ = \frac{3 m g}{k}$