Question

In figure showwn below , all the diodes are ideal.

The value of current I is ___ mA.

• A. 4

Answer 1

The correct option is A 4
Since, the cathode of $D_1$ is at lowest potential.
$\therefore D_1$ will be ON & thus $V_0$ = 1 V

$\therefore D_{2}and{D}_3$ are OFF

$I=\frac{5-1}{1k\Omega }=4mA$