Question

In figure, the velocities are in ground frame and the cylinder is performing pure rolling on the plank, velocity of point 'A' would be

• A. $2V_C$
• B. $2V_C+V_P$
• C. $2V_C-V_P$
• D. $2(V_C-V_P)$

Answer 1

The correct option is C $2V_C-V_P$


For pure rolling velocity of the point of contact has to be equal to the velocity of the surface

Let us say cylinder rolls with angular velocity $\omega$.

At point B,

$V_C-\omega r=V_P\Rightarrow \omega r=V_C-V_P$

At point A,

$V_A=V_C+\omega r=2V_C-V_P$