1
Question
In figure, the wires P1Q1 and P2Q2 are made to slide on the rails with same speed of 5 cm s−1. In this region, a magnetic field of 1 T exists. The electric current in the 9 Ω resistance is
In figure, the wires P1Q1 and P2Q2 are made to slide on the rails with same speed of 5 cm s−1. In this region, a magnetic field of 1 T exists. The electric current in the 9 Ω resistance is
Open in App
Solution
The correct options are
B zero, if both wires slide in opposite directions
C 0.2 mA, if both wires move towards left
Each wire can be replaced by a battery whose emf is equal to
Blv=1×4×10−2×5×102
=20×10−4V.
The polarity of the battery can be given by Fleming's right hand rule.
When both wire move in opposite direction, the circuit diagram looks like as shown in figure.
Effective emf of two batteries shown in E(=0 V)
Hence , in this case current in 9 Ω resistor is zero.
When both wires move in same direction, the circuit diagram looks like as shown in figure.
Effective emf of two batteries shown is E=20×10−4V
and internal resistance is 1 Ω.
Hence, current in the circuit is
i=20×10−410=0.2 mA
Hence, choice (c) is correct and choice (a) is wrong.
B zero, if both wires slide in opposite directions
C 0.2 mA, if both wires move towards left
Each wire can be replaced by a battery whose emf is equal to
Blv=1×4×10−2×5×102
=20×10−4V.
The polarity of the battery can be given by Fleming's right hand rule.
When both wire move in opposite direction, the circuit diagram looks like as shown in figure.
Effective emf of two batteries shown in E(=0 V)
Hence , in this case current in 9 Ω resistor is zero.
When both wires move in same direction, the circuit diagram looks like as shown in figure.
Effective emf of two batteries shown is E=20×10−4Vand internal resistance is 1 Ω.
Hence, current in the circuit is
i=20×10−410=0.2 mA
Hence, choice (c) is correct and choice (a) is wrong.
Suggest Corrections
0
Similar questions
