In figure there are two concentric circles with centre O and of radii 5 cm and 3 cm. From an external point P tangents PA and PB are drawn to these circles. If AP = 12 cm find the length of BP
A
4√10 cm
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B
2√10 cm
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C
√10 cm
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D
3√10 cm
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Solution
The correct option is A4√10 cm Two concentric circles with center O. OA is 5 cm and OB is 3 cm. Join OP. Now, in △OAP ∠OAP=90∘ (Angles between radius and tangent) OA2+AP2=OP2 52+122=OP2 OP=13 cm In △OBP, OB2+BP2=OP2 32+BP2=132 BP=√160=4√10 cm