Question

In figure, $△AHK$ is similar to $△ABC$. If $AK-10cm,BC-3.5cm$ and $HK-7cm$ find $AC$?

Answer 1

Since $\Delta$ AHK $\sim \Delta$ ABC

So $\frac{AK}{AC}=\frac{HK}{BC}$

So AC $=\frac{AK\times BC}{HK}=\frac{10\times 3.5}{7}=5cm$