In figure, X and Y are the points on equal sides of AB and AC such that AX=AY. Show that XC=BY.
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Solution
In ΔABC AB=AC (given) and AX=AY (given) AB–AX=AC–AY BX=CY ….(i) Now in ΔBXC and ΔBYC BX=CY [from (i)] BC=BC (common) ∠B=∠C (angle opp. to equal sides are equal) ΔBXC=ΔBYC (by SAS property) XC=BY (by c.p.c.t) Hence proved.