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Question

In first 1000 natural numbers, how many numbers exists such that when divided by 11 leaves a remainder of 8?


A

92

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B

93

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C

91

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D

90

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Solution

The correct option is C

91


The numbers required will be 8,19,30,41,.......,998

8 + (n-1)11 = 998

(n-1)11 = 990

n = 91


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