In first 1000 natural numbers, how many numbers exists such that when divided by 11 leaves a remainder of 8?
92
93
91
90
The numbers required will be 8,19,30,41,.......,998
8 + (n-1)11 = 998
(n-1)11 = 990
n = 91
In first 1000 natural numbers, how many numbers exists such that when divided by 7 leaves a remainder of 6?
How many numbers are between 10 to 30, that leave a remainder of '2' when divided by 3?
How many numbers lie between 10 and 300 which when divided by 4 leaves a remainder 3