In Fresnel's bi-prism experiment, a mica sheet of refractive index $1.5$ and thickness $6 \times 10^{- 6} m$ is placed in the path of one of interfering beams as a result of which the central fringe gets shifted through five fringe widths.The wavelength of light used is

6000 A^{o}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

8000 A^{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4000 A^{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2000 A^{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $6000 A^{o}$
Since the central fringe gets shifted by five fringe widths, this means the change in path difference caused is $5 λ$ .
Therefore, $t (μ - 1) = 5 λ$
Hence, $λ = \frac{(6 \times 10^{- 6}) (0.5)}{5} m = 6000 A^{\circ}$

Suggest Corrections

Similar questions

Q. In Fresnel's biprism expt., a mica sheet of refractive index 1.5 and thickness 6

\times

^{- 6}

m is placed in the path of one of interfering beams as a result of which the central fringe gets shifted through 5 fringe widths. The wavelength of light used is

Q. On placing a thin sheet of mica of 1.2

μ

m thickness in the path of one of the interfering beams in a bi-prism experiment, it is found that the central bright band shifts to a distance equal to the width of a bright fringe. The refractive index of mica is

\frac{x}{2}

. Find

x

. (

λ = 600

nm).

Q. A thin sheet of plastic having a refractive index of 1.60 is placed in the path of the interfering beams in an interference experiment using light of 589 nm wavelength. The central fringe shifts through 12 fringes. Calculate the thickness of the sheet in

μ m

(rounded off to nearest integer).

In placing a thin sheet of mica of thickness $12 \times 10^{- 5} c m$ in the path of one of the interfering to beam in YDSE, the central fringe shifts equal to a fringe width. Find the refractive index of mica. Given $λ = 600 n m$ .

Q. When a mica sheet of thickness 7 microns and

μ = 1.6

is placed in the path of one of interfering beams in the

Y D S E

, then the central fringe gets at the position of the seventh bright fringe. What is the wavelength of light used ?

Join BYJU'S Learning Program

In Fresnel's bi-prism experiment, a mica sheet of refractive index 1.5 and thickness 6×10−6m is placed in the path of one of interfering beams as a result of which the central fringe gets shifted through five fringe widths.The wavelength of light used is

The correct option is C 6000AoSince the central fringe gets shifted by five fringe widths, this means the change in path difference caused is 5λ.Therefore, t(μ−1)=5λHence, λ=(6×10−6)(0.5)5m=6000A∘

In Fresnel's bi-prism experiment, a mica sheet of refractive index $1.5$ and thickness $6 \times 10^{- 6} m$ is placed in the path of one of interfering beams as a result of which the central fringe gets shifted through five fringe widths.The wavelength of light used is

The correct option is C $6000 A^{o}$
Since the central fringe gets shifted by five fringe widths, this means the change in path difference caused is $5 λ$ .
Therefore, $t (μ - 1) = 5 λ$
Hence, $λ = \frac{(6 \times 10^{- 6}) (0.5)}{5} m = 6000 A^{\circ}$