Question

In Freundlich adsorption isotherm, slope of $AB$ line is :



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Answer 1

According to Freundlich adsorption isotherm

$\frac{x}{m}-k.P^{1/n}(n>1)$

$log\frac{x}{m}=logk+\frac{1}{n}logP$

$\text{So, in the plot of}log\frac{x}{m}\text{vs log P, the slope is}\frac{1}{n},$

$where\frac{1}{n}\text{varies from 0 to 1 (since, n >1)}$

Hence, option (b) is correct.