Question

In Freundlich Adsorption isotherm, the value of 1/n is :

• A. $1$ in case of physical adsorption
• B. $1$ in case of chemisorption
• C. between $0$ and $1$ in all cases
• D. between $2$ and $4$ in all cases

Answer 1

The correct option is C between $0$ and $1$ in all cases

$\text{Freundlich adsorption isotherm}$

$\frac{x}{m}=k{p}^{\frac{1}{n}}$

$\begin{array}{c}\text{at low pressure}\\ \frac{x}{m}\alpha p\Rightarrow \frac{x}{m}=kp\end{array}$

$\text{At high pressures}\frac{x}{m}\alpha p^0$

$\begin{array}{c}\text{At intermediate pressure}\\ \frac{x}{m}\alpha p^{\frac{1}{n}}\\ \frac{1}{n}\text{is lies between}0\text{to}1\end{array}$