In fructose and glucose the possible optical isomers are:

12, 12

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8, 16

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16, 8

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4, 12

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Solution

The correct option is B 8, 16
Fructose contains three chiral carbon atom and glucose contain 4 chiral carbon atoms.
The Number of possible Optical isomers for Fructose are $2^{3} = 8$
The Number of possible Optical isomers for Glucose are $2^{4} = 16$
8, 16 is the Answer

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