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Question

In further 10 minutes it will cool from 38 to

A
36
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B
36.4
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C
37
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D
37.5
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Solution

The correct option is B 36.4
We have θθs = (θ0θs)ekt.....(1)Where =initial temperature of body =40θ=temperature of body after time t θs=temperature of surrounding Since body cools from 40 to 38 in 10 min, we have 3830=(4030)e10k....(2)Let after 10 min, the body temp be θ,θ30=(3830)e10k.....(3)Dividing eq(2) by eq(3) gives 8θ30=108θ30=6.4θ=36.4o


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