In G.P. (p+q)th term is m, (pāq)th term is n, then pth term is
A
nm
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B
√nm
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C
mn
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D
√mn
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Solution
The correct option is B√nm Let the first term of G.P be 'a' and common ratio be 'r' given Tp+q=arp+q−1=mTp−q=arp−q−1=n then multiplying the above two equations : mn=a2r2p−2=(arp−1)2⇒arp−1=√mn but arp−1 is the pth term of the G.P hence Tp=√mn