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Law of Dominance

In garden pea...

Question

In garden pea, round shape of seeds is dominant over wrinkled shape. A pea plant heterozygous for round shape of seed is selfed and 1600 seeds produced during the cross are subsequently germinated. How many seedlings would have the parental phenotype?

A

1600

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B

800

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C

400

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D

1200

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Solution

The correct option is D 1200
As pea plant is heterozygous for round shape, its genotype would be Rr.
Parents: Rr x Rr
Progeny: RR Rr Rr rr
Phenotypically, the ratio will be 3:1. i.e., only rr seeding will show wrinkled phenotype, rest will show round shape. When the total number of seed is 1600 so
1200 - Round shape (RR, Rr)
400 - Wrinkled (rr).
Thus, the correct answer is option (D).

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