Question

In gaseous reaction, $3H_2+N_2\rightleftharpoons 2N{H}_3$, the partial pressure of $H_2$ and $N_2$ are $0.4$ and $0.8atm$. respectively. The total pressure of the whole system is $2.8atm$. What will be the value of $K_p$?

Answer 1

$N_2+3H_2\to 2N{H}_3$

partial pressures of $H_2$ and $N_2$ are 0.4 and 0.8 atm

so partial pressure of $2N{H}_3$ = 1.6 atm

$Kp=\frac{[NH3{]}^2}{\left[N_2\right][H_2{]}^3}$

$=\frac{{1.6}^2}{0.8\times {0.4}^3}$

$=2.56/0.0512$

= 50