In given circuit when voltmeter is connected across 2Ω gives reading 5V. When same voltmeter is connected across 3Ω the reading will be
A
5V
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B
7.5V
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C
2.5V
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D
4V
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Solution
The correct option is B 7.5V Let resitance of voltmeter be RV. Potential difference across 3Ω is 15V. So I=153=5A By v=iR⇒5=i×2⇒i=2.5A RV=2Ω Req=65+2=165Ω ∴I=20×516 ∴ potential diference across 2Ω is =20×516×2=20×58 So voltmeter reading is 20−20×58=7.5V