In given complex $[C r (C_{2} O_{4})_{2} (H_{2} O)_{2}]^{-}$ :
(a)The oxidation number of $C r$ is $x$
(b) The coordination number of $C r$ is $y$
Then $x + y =$ ?

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Solution

The correct option is B 9
oxidation number of Cr is +3, $x$ = 3
coordination number of Cr is 6, $y$ = 6
So, $x + y$ = 6+3 = 9
Hence option B is correct

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In given complex [Cr(C2O4)2(H2O)2]−:(a)The oxidation number of Cr is x(b) The coordination number of Cr is yThen x+y=?

The correct option is B 9oxidation number of Cr is +3, x = 3coordination number of Cr is 6, y = 6So,x+y = 6+3 = 9Hence option B is correct

In given complex $[C r (C_{2} O_{4})_{2} (H_{2} O)_{2}]^{-}$ :
(a)The oxidation number of $C r$ is $x$
(b) The coordination number of $C r$ is $y$
Then $x + y =$ ?

The correct option is B 9
oxidation number of Cr is +3, $x$ = 3
coordination number of Cr is 6, $y$ = 6
So, $x + y$ = 6+3 = 9
Hence option B is correct