AB∥CD, EF⊥CD, ∠GED=126∘
According to the question,
∠FED=90∘(EF⊥CD)
Now,
∠AGE=∠GED (Since, AB∥CD and GE is transversal. Alternate interior angles.)
∴∠AGE=126∘
Also,
∠GEF=∠GED−∠FED
⇒∠GEF=126∘−90∘
⇒∠GEF=36∘
Now,
∠FGE+∠AGE=180∘ (Linear pair)
⇒∠FGE=180∘−126∘
⇒∠FGE=54∘