Question

In given figure a ladder is placed in such a way that its foot is at a distance of 5 m from a wall and its tip reaches a window 12 m above the ground. Determine the length of the ladder.

Answer 1

Let AB be the ladder and B be the window Then,

$BC=12m$ and $AC=5m$

Since $△ABC$ is a right triangle right-angled at C.

By pythagoras theoram, we have

$\therefore$ ${AB}^2={AC}^2+{BC}^2$

$\Rightarrow$ ${AB}^2=5^2+{12}^2=169$

$\Rightarrow$ $AB=13m$

Hence, the length of the ladder is $13m.$