In given figure- CO - OD - OCD -30- Now find the - AOB - -3 MARKS-

Concept: 1 Mark Solution: 2 Marks Sum of the angles of a triangle is 180^∘. Since OC = OD therefore ∠ OCD = ∠ ODC [Angles opposite to equal sides OC amp; O ...

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Standard VIII

Mathematics

Angle Sum Property of a Polygon

In given figu...

Question

In given figure, CO = OD & $∠ O C D = 30^{\circ}$ . Now find the $∠ A O B$ ? [3 MARKS]

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Solution

Concept: 1 Mark
Solution: 2 Marks

Sum of the angles of a triangle is $180^{\circ}$ .

Since OC = OD therefore $∠ O C D = ∠ O D C$
[Angles opposite to equal sides OC & OD are also equal]

$\Rightarrow ∠ C O D = 180^{\circ} - (30^{\circ} + 30^{\circ}) = 120^{\circ}$

Hence, $∠ A O B = ∠ C O D$ [Vertically Opposite Angles]

$∴ ∠ A O B = 120^{\circ}$

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In given figure, CO = OD & ∠OCD=30∘. Now find the ∠AOB? [3 MARKS]

Concept: 1 Mark Solution: 2 Marks Sum of the angles of a triangle is 180∘. Since OC = OD therefore ∠OCD=∠ODC [Angles opposite to equal sides OC & OD are also equal] ⇒∠COD=180∘−(30∘+30∘)=120∘ Hence, ∠AOB=∠COD [Vertically Opposite Angles] ∴∠AOB=120∘

In given figure, CO = OD & $∠ O C D = 30^{\circ}$ . Now find the $∠ A O B$ ? [3 MARKS]