In ΔADE and ΔABC,
∠ADE=∠B and ∠A=∠A
So, by AA criteria, ΔADE∼ΔABC, then,
⇒ ADAB=DEBC
⇒ ADAE+EB=DEBC
⇒ 3.83.6+2.1=DE4.2
⇒ DE=2.8cm
In the adjoining figure, AD=5.6 cm, AB=8.4cm, AE=3.8cm and AC=5.7cm. Show that DE||BC.