Question

In given figure, If BC = 5 cm, $\angle ABC={60}^{\circ },$ then AB-AC is

• A.
  4 cm
• B.
  2 cm
• C.
  3 cm
• D.
  7 cm

Answer 1

The correct option is B

2 cm
Whenever we have to find the difference of other two sides, we take the difference of other two sides on this ray sides by taking B as centre of radius equal to the difference of other two sides,

Here we have to find the differences of other remaining two sides, definately it will be equal to 2 cm.

Also,
$\therefore$ ADC is an isosceles triangle, point A is lying as the Perperticular bisector of line segment CD,

So, we can conclude point A is equi-distant from the ends of line segment CD, that's why this triangle ADC from an isosceles triangle and we can clearly write

$AB-AC\Rightarrow AB-AD=2cm\Rightarrow \text{Option (b) 2 cm.}$