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Question

In given figure, if $$\displaystyle \angle OAB$$ = $$\displaystyle 40^{\circ},$$ then $$\displaystyle \angle ACB$$ is equal to:
426551_87647954633e42c893b19ab66b2cbaf8.png


A
50
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B
40
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C
60
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D
70
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Solution

The correct option is A $$\displaystyle 50^{\circ}$$
In the circle $$OA=OB =$$ Radius
So, $$\angle OAB=\angle OBA=40^°$$
Therefore, $$\angle AOB=180^°-40^°-40^°=100^°$$             {Angle sum property}
We know in a circle the angle subtended by an arc at the center is twice that of the angle made on the circle.
Therefore, $$\angle ACB=\dfrac{\angle AOB}{2}=50^°$$

Mathematics

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