Question

# In given figure, if $$\displaystyle \angle OAB$$ = $$\displaystyle 40^{\circ},$$ then $$\displaystyle \angle ACB$$ is equal to:

A
50
B
40
C
60
D
70

Solution

## The correct option is A $$\displaystyle 50^{\circ}$$In the circle $$OA=OB =$$ RadiusSo, $$\angle OAB=\angle OBA=40^°$$Therefore, $$\angle AOB=180^°-40^°-40^°=100^°$$             {Angle sum property}We know in a circle the angle subtended by an arc at the center is twice that of the angle made on the circle.Therefore, $$\angle ACB=\dfrac{\angle AOB}{2}=50^°$$Mathematics

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