Question

In given figure of cube and cuboid, which one has a greater surface area?

• A. Cube
• B. Cuboid
• C. Cant compose
• D. None

Answer 1

The correct option is B Cuboid

Total surface area of cuboid $=2(lw+wh+hl)$
$h=3,l=8,w=6$

$TSA=2(8\times 6+6\times 3+3\times 8)$
$=2(48+18+24)=90\times 2=180{cm}^2$

TSA of cube $=6a^2=6{\left(5\right)}^2$
$=25\times 6=150{cm}^2$

TSA of cuboid > TSA of cube.